POLYNOMIALS
LESSON-4, DAY 2
GOOD MORNING EVERYONE!!
Let us go through the guidelines for the blog once again:
POLYNOMIALS
LESSON-4, DAY 2
GOOD MORNING EVERYONE!!
GOOD MORNING EVERYONE!!
· Red, is to be π in your π
· Blue is to be π by ➤
· Green is to be π¬ππ for home work
- take your SET-A Mathematics π
- Ourπ. It will be π, if you use good presentation and cursive π
- Make a column on the RHS, if you need to do any rough work
- Leave ⓶ lines where you finished yesterday’s work and draw a horizontal line
- Write today's π
· Red, is to be π in your π
· Blue is to be π by ➤
· Green is to be π¬ππ for home work
- take your SET-A Mathematics π
- Ourπ. It will be π, if you use good presentation and cursive π
- Make a column on the RHS, if you need to do any rough work
- Leave ⓶ lines where you finished yesterday’s work and draw a horizontal line
- Write today's π
LEARNING OUTCOMES Covered So far:
1. RECALL WHAT IS AN ALGEBRAIC EXPRESSION AND DEFINE POLYNOMIAL.
2. RECALL AND DEFINE TERMS AND COEFFICIENTS.
3. DEFINE DEGREE OF A POLYNOMIAL
4. CLASSIFY THE POLYNOMIALS ON THE BASIS OF NUMBER OF TERMS AND DEGREE.
5. COMPREHEND AND MEMORIZE ABOUT SOME SPECIAL POLYNOMIALS.
6. EVALUATE VALUE OF A POLYNOMIAL
6. EVALUATE VALUE OF A POLYNOMIAL
7 .EVALUATE ZERO OF A POLYNOMIAL.
TODAY'S LEARNING OUTCOMES:
I WILL BE ABLE TO:
1) know that a polynomial can be ÷ by another polynomial.
2) apply division process to polynomials.
3) comprehend remainder theorem.
4) apply remainder theorem to calculate the remainder when a polynomial is ÷ by another polynomial.
Q1) 10 - 6 = 4 , here 4 is known as a (remainder / sum)
Q2) 10 ÷ 2 = 5,here 5 is known as a (remainder/ quotient)
Q3) (10x - 1) - (3) = (10x -4), here (10x -4) is a _____
Q4) (2x + 4) ÷ 2 = POSSIBLE ? , please watch the following video (for just first 4min 45 seconds) to check
please observe the image given below
Q5) Divide (2x² + 4x - 7) ÷ (x + 1)
A5) STEP-1: Write in division format
STEP-2: Divide 2x² by x {1st term of dividend by 1st term of divisor}
STEP-3: Multiply (x + 1) by the answer from step-2
STEP-4: Subtract & bring down -7{This forms the new dividend}
STEP-5: Divide 2x by x {1st term of new dividend by 1st term of divisor}
STEP-6: Multiply (x + 1) by the answer from step-5
STEP-7: Subtract. The remainder is ____
Q6) 11 ÷ 2, gives, quotient = ___, remainder = ___
Q7) In Q6, 11 = 2 × ___ + ___ {Hint: substitute quotient & remainder}
Q5) Divide (2x² + 4x - 7) ÷ (x + 1)
A5) STEP-1: Write in division format
STEP-2: Divide 2x² by x {1st term of dividend by 1st term of divisor}
STEP-3: Multiply (x + 1) by the answer from step-2
STEP-4: Subtract & bring down -7{This forms the new dividend}
STEP-5: Divide 2x by x {1st term of new dividend by 1st term of divisor}
STEP-6: Multiply (x + 1) by the answer from step-5
STEP-7: Subtract. The remainder is ____
The above process
gives us two OUTPUTS:
FIRST: The quotient
SECOND: The remainder
Please ➤π
Please ➤π
You heard this word "tedious", in the above audio.
Please write this new word in your diary with today's date:
TEDIOUS : means , too long, slow or dull
Cleaning of our rivers such as Yamuna & Ganga
had become a tedious process,
because,
we as the citizens of India
were not making full contributions to the process.
We were still
littering the rivers through our selfish acts.
COVID-19
has corrected this doing of ours.
Read about SDG-14 : Life below water
Q7) In Q6, 11 = 2 × ___ + ___ {Hint: substitute quotient & remainder}
In the questions given below p(x) is divide by g(x). Q8 & Q12 are done as sample for you as an application of remainder theorem. Solve the other questions as per the steps given in the tableπ
VERY IMPORTANT NOTE:
If the divisor is given as ( 2 + 3x),
Write as (3x + 2),
or
If the divisor is given as ( 2 - 3x),
Write as (-3x + 2),
before applying remainder theorem
HOME WORK:
Ex. 2.3- Q1,2 & 3
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